The nut (ignoring details) must at least provide around 100 pounds of sealing force for the 3 gaskets, but if only 2 were used only around 66 pounds.īeyond the scope here. So lets say we have 20 square inches of gasket material (both sides of all 3 gaskets) in contact with the tank. The total force applied to ALL the gaskets is the force applied applied by the inclined plane divided by the total surface area. The NUT (remember from physics class) rides an inclined plance to create force against the gaskets. But consider a deeper bulkhead that has say 5 PSI of pressure on it. The gross contact area of all of the gaskets combines is what needs to be compressed by the nut. Click to expand.Likely no harm in this case, but consider the surface contact area of each gasket.
